Question

For an A.P., t1=2, tn= 41 and Sn =860. What is
the value of n?
(A) 31 (B) 30 (C) 41 (D) 40​

Answer 1

Answer:

(C) 41 is the correct answer

Step-by-step explanation:

T1=2

Tn=41

Sn=860

n=?

Sn=n/2{2a+(n-1)d

860=n/2{2×2+(n-1)d}

860=n/2(t1+tn)

860=n/2(2+41)

860=n/2(43)

n=(860×2)+43

n=40

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