Math, asked by aarushigala12, 3 months ago

For an A.P., t1 = 7 & t12 = 29, find S12

Answers

Answered by raoclanleadr

0

Answer:

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Answered by Faizansabri

0

Step-by-step explanation:

t1=a=7
t12=29
a+(1-1)d=7
a=7
t12=a+(12-1)d
29=7+11d
11d=29-7
d=2
sn=n/2(2a+(n-1)d
s12=12/2(2×7+(12-1)2)
s12=6(14+11×2)
s12=6(14+22)
s12=6×36
s12=216

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