Question

for an A.P t11=16,t=21=find t41​

Answer 1

Answer:

$t \:( 11) = t \: + 10d$

$t(11) = 16$

$t = 21$

$t(41) = t + 40d$

$16 = 21 + 10d$

$16 - 21 = 10d$

$- 5 = 10d$

$d = \frac{ - 1}{2}$

$t(41) = 21 + 40 \times \frac{ - 1}{2}$

$t(41) = 21 - 20$

$t(41) = 1$