Math, asked by silenceluv, 5 months ago

For an A.P. t2=1 and t6=13 then t1​

Answers

Answered by Anonymous
1

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T6-T2=13-1

T1+5D-(T1+D)=12

T1+5D-T1-D=12

4D=12

D=3

......

T6=13

T1+5D=13

T1+15=13

T1=-1

HOPE IT HELPS

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