Question

• For an A.P. t3=13 and t7=29. What is the value of t5? >A] 21>© 19>B 18>B В>20​

Answer 1

Answer:

Given, t3 = 13, t7 = 29

. i. e., t + 2d = 13, t + 6d = 29

Subtract both equations

So we get,

d = 4

Then, t + 2d = 13

t + 2×4 = 13

t = 5

t5 = t + 4d

= 5 + 4×4

t5 = 21

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Answer 2

Step-by-step explanation:

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