Question

for an A.P .t3=8 and t4=12 find the common difference d​

Answer 1

Step-by-step explanation:

t3= 8

t4= 12

d= t4-t3

d=12-8=4

Answer 2

Answer:

d = 4

Step-by-step explanation:

We know that,

$t_{n} = a + (n - 1)d$

Given: t3 = 8 & t4 = 12

To Find: the common difference d

Solution:

A/Q,

$t_{3} = a + (3 - 1)d \\ 8 = a + 2d \: \: \: ...(i)$

Again,

$t_{4} = a + (4 - 1)d \\ 12 = a + 3d \: \: \: ...(ii)$

On substracting (i) from (ii),

12 - 8 = (a + 3d) - (a + 2d)

=> 4 = a - a + 3d - 2d

d = 4 ANS.