Math, asked by danish6859, 1 year ago

For an A.P.t6= -10 and b14 = -34
Find the value of t10.​

Answers

Answered by kartik2507
2

Answer:

t10 = -22

Step-by-step explanation:

t6 = a + 5d = -10

t14 = a + 13d = -34

t14 - t6

a + 13d - (a + 5d) = -34 - (-10)

a + 13d - a - 5d = - 34 + 10

8d = -24

d = -24/8

d = - 3

substitute d = -3 in t6

a + 5d = - 10

a + 5(-3) = -10

a - 15 = -10

a = -10 + 15

a = 5

t10 = a + 9d

= 5 + 9(-3)

= 5 - 27

= - 22

therefore 10th term is = -22

hope you get your answer

Answered by raiarchana315
0

Answer:

10th term is -22.

Step-by-step explanation:

i think it will help you

Similar questions