For an A.P.t6= -10 and b14 = -34
Find the value of t10.
Answers
Answered by
2
Answer:
t10 = -22
Step-by-step explanation:
t6 = a + 5d = -10
t14 = a + 13d = -34
t14 - t6
a + 13d - (a + 5d) = -34 - (-10)
a + 13d - a - 5d = - 34 + 10
8d = -24
d = -24/8
d = - 3
substitute d = -3 in t6
a + 5d = - 10
a + 5(-3) = -10
a - 15 = -10
a = -10 + 15
a = 5
t10 = a + 9d
= 5 + 9(-3)
= 5 - 27
= - 22
therefore 10th term is = -22
hope you get your answer
Answered by
0
Answer:
10th term is -22.
Step-by-step explanation:
i think it will help you
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