Question

for an A.P. t6 = -12 and t14 = -34 find the value of t10​

Answer 1

Step-by-step explanation:

tn = a+( n-1) × d

t6= a + (6-1) × d

t6 = a+ 5d

-12 = a+5d

therefore a+5d = -12 --------- (equation no 1 )

t14 = a+(14-1) ×d

t14 = a+13d

-34 = a + 13d

therefore a+3d = -34 ----------( equation no 2)

subtracting equation 1 & 2

a+5d = -12

a+3d = -34

___________

2d = 12

d = 6

t10 = a +(n - 1) d

= a +(10-1) 6

= a+ 9×6

= a+54

a = -54.