Question

For an A.P., t7 = 10 and t13 = 34. Find the value of t10.​

Answer 1

Answer:

22

Step-by-step explanation:

given it is an Arithmetic Progression

7th term =10

13th term =34

difference between terms =13-7=6 terms are in between 7 and 13

difference between progression =34-10=24

it is an AP so the difference between terms should be equal so 24/ no of terms =24/6=4

difference between terms d =4

now

t7=10

t8=10+4=14

t9=14+4=18

t10=18+4=22

t11=22+4=26

t12=26+4=30

t13=30+4=34

Answer 2

Answer

22

Step-by-step explanation:

given it is an Arithmetic Progression

7th term =10

13th term =34

difference between terms =13-7=6 terms are in between 7 and 13

difference between progression =34-10=24

it is an AP so the difference between terms should be equal so 24/ no of terms =24/6=4

difference between terms d =4

now

t7=10

t8=10+4=14

t9=14+4=18

t10=18+4=22

t11=22+4=26

t12=26+4=30

t13=30+4=34