Question

For an A.P.,t7=10 and t13=34.Find the value of t10
please help! ​

Answer 1

Answer:

tn= a+(n-1)d

t7=a+(7-1)d=a+6d=10

t13=a+(13-1)d=a+12d=34

{a+12d}-{a+6d}=34-10

or, a+12d-a-6d=24

or, 6d=24

therefore, d= 24/6=4

a+6d=10

or, a+6(4)=10

therefore, a= 10-6(4)=10-24=(-14)

t10= a+(10-1)d

= (-14)+9(4)

= (-14)+36

= 22(Ans:-)

Answer 2

Answer:

tn= a+(n-1)d

t7=a+(7-1)d=a+6d=10

t13=a+(13-1)d=a+12d=34

{a+12d}-{a+6d}=34-10

or, a+12d-a-6d=24

or, 6d=24

therefore, d= 24/6=4

a+6d=10

or, a+6(4)=10

therefore, a= 10-6(4)-10-24=(-14)

t10= a +(10-1)d

= (-14)+9(4)

= (-14)+36

= 22(Ans:-)

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