For an acute angle Aand B if tanA=1*√3 and sinB=1*2,then cos(A+B)=........
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tan A = 1/√3 ( NOT 1*√3)
tan 30°= 1/√3
so A = 30°
sinB = 1/2
sin 30° = 1/2
so B=30°
Cos(A + B) =Cos(30+30)=cos(60°)=½
if you are satisfied with the answer mark it as brainliest
tan 30°= 1/√3
so A = 30°
sinB = 1/2
sin 30° = 1/2
so B=30°
Cos(A + B) =Cos(30+30)=cos(60°)=½
if you are satisfied with the answer mark it as brainliest
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