Question

For an amplitude modulation wave the maximum amplitude is found to be 10 volt while minimum is found to be to calculate modulation index why is modulation index is kept denser

Answer 1

Solution :

Amax=Ac+Am=10vAmax=Ac+Am=10v

Amin=Ac−Am=2vAmin=Ac−Am=2v

=> 2Ac=12v2Ac=12v

or Ac=6vAc=6v

and Am=4VAm=4V

μ=AmAcμ=AmAc

=46=46

=23

Answer 2

Solution :

Amax=Ac+Am=10vAmax=Ac+Am=10v

Amin=Ac−Am=2vAmin=Ac−Am=2v

=> 2Ac=12v2Ac=12v

or Ac=6vAc=6v

and Am=4VAm=4V

μ=AmAcμ=AmAc

=46=46

=23