for an angle of incidence of 45 degree at at the top surface of a glass slab as shown in figure what is the maximum refractive index of Glass for total internal reflection
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5
Answer:
The answer will be √3/2
Explanation:
According to the figure, if we apply Snell's law:
μ == sin i/sin r
Now it is stated that the angle of incidence is 45 degree
Therefore, sin r = sin i/μ = 1/μ√2
The total internal reflection sin i1 = 1/μ
Therefore we can also say that , i1 = 90 -r
Therefore sin(90-r) = 1/μ
=> cos r = 1/μ
cos r = √1- sin^2r = √1-1/2μ^2 = √2μ^2-1/2μ^2
from here we can get μ = √3/2
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17
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