For an angle θ with the point (−5, −12) on its terminating side, what is the value of cosine?
SamRaiden:
I hope the cos will always be negative there
is it correct
as in third quadrant it is alway negative
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As can be seen from the image, the point (-5, -12) lies in the third quadrant.
To get the cosine, we need the hypotenuse
Hypotenuse = √(5² + 12²)
= √169
= 13
Cosine = Adjacent/hypotenuse
= -5/13
= - 0.3846
To get the cosine, we need the hypotenuse
Hypotenuse = √(5² + 12²)
= √169
= 13
Cosine = Adjacent/hypotenuse
= -5/13
= - 0.3846
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