Question

for an ap 1/6,1/4,1/3 ...........find t20 and t10

Answer 1

AP:1/6,1/4,1/3........................ a=1/6,d=1/12
A20=a+(n-1)d
=1/6+19 ✖ 1/12
= 7/4
A10=a+(n-1)d
=1/6+9 ✖ 1/12
=11/12

Answer 2

Ans : a =1/6
d = 1/4 - 1/6
= 3-2/12
= 1/12
An = a+ (n-1)d
A 20 = 1/6 + ( 20-1) ×1/12
= 1/6 + 19× 1/12
= 2+19/12
= 21/20
A10 = 1/6+ ( 10-1) 1/12
= 1/6+ 9/12
= 2+9 /12
= 11/12
So, A 20=21/20 and An = 11/12
I hope its help u.......
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