Question

for an ap 1 , 7, 13 , 19......find t18 , t31 , t56 , t101 , t202 what is value
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Answer 1

$\huge\purple{\underline{\underline{\pink{Ans}\red{wer:-}}}}$

$\sf{The \ values \ are:-}$

$\sf{t18=103,}$

$\sf{t31=181,}$

$\sf{t56=331,}$

$\sf{t101=601,}$

$\sf{t202=1207}$

$\sf\orange{Given:}$

$\sf{The \ given \ A.P. \ is}$

$\sf{\implies{1,7,13,19,…}}$

$\sf\pink{To \ find:}$

$\sf{t18,t31,t56,t101 \ and \ t202}$

$\sf\green{\underline{\underline{Solution:}}}$

$\sf{The \ given \ A.P. \ is}$

$\sf{\implies{1,7,13,19,…}}$

$\sf{Here,\ a=1, \ d=7-1=6}$

$\sf{\implies{tn=a+(n-1)d}}$

$\sf{... formula}$

______________________________

$\sf{t18=1+(18-1)6}$

$\sf{t18=1+17\times6}$

$\sf{t18=1+102}$

$\sf{t18=103}$

______________________________

$\sf{t31=1+(30-1)6}$

$\sf{t31=1+30\times6}$

$\sf{t31=1+180}$

$\sf{t31=181}$

______________________________

$\sf{t56=1+(56-1)6}$

$\sf{t56=1+55\times6}$

$\sf{t56=1+330}$

$\sf{t56=331}$

______________________________

$\sf{t101=1+(101-1)6}$

$\sf{t101=1+100\times6}$

$\sf{t101=1+600}$

$\sf{t101=601}$

______________________________

$\sf{t202=1+(202-1)6}$

$\sf{t202=1+201\times6}$

$\sf{t202=1+1206}$

$\sf{t202=1207}$

$\sf\purple{\tt{\therefore{The \ values \ are:-}}}$

$\sf\purple{\tt{t18=103,}}$

$\sf\purple{\tt{t31=181,}}$

$\sf\purple{\tt{t56=331,}}$

$\sf\purple{\tt{t101=601,}}$

$\sf\purple{\tt{t202=1207}}$