For an AP 7, 11, 15, 19,...... find the sum of first 50 terms. *
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Step-by-step explanation:
AP=7,11,15,19..........
In order to find Sn
a=7 , d=4
Sn=n/2{2a+(n-1)d}
S50=50/2{2(7)+(50-1)4}
S50=25{14+(49)4}
S50=25{14+196}
S50=25{210}
S50=5250
THEREFORE THE SUM OF FIRST FIFTY TERMS ARE :- 5250
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