Question

for an ap a=10,d=1.find S30​

Answer 1

Step-by-step explanation:

we know that,

Sn =

$\frac{n}{2} (2a +(n - 1)d)$

here, a=10,d=1,n=30

=> Sn =

$\frac{30}{2} (20 + 29 \times 1)$

= 15×49 = 735

therefore 735 is your answer

Answer 2

$\sf\green{\underline{\sf Given:-}}$

A = 10

D = 1

$\sf\orange {\underline {\sf To\:Find:-}}$

$S_{30}$

$\sf\blue {\underline {\sf Now:-}}$

$s_{n}= \frac{n}{2} (2a + (n - 1)d)$

$s _{30} = \frac{30}{2} (2 \times 10 + (30 - 1)1)$

$s _{30 }= 15(20 + 29)$

$s _{30} = 15 \times 49$

$s _{30} = 735$