For an AP, a = −10, d = 4. find S10 term
a. 90 b. 80 c. 100 d. 110
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Answered by
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given÷
a=-10,d=4
to find S10
S10=n/2(2a+(n-1)d)
S10=10/2(2×-10+9×4)
S10=5(-20+36)
S10=5(16)
S10=80
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0
Answer:
The answer of given A.P
s¹⁰=80 is answer of given question
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