Question

for an AP• if a=6 and d=3, the find s10

Answer 1

sum of nth terms - n/2 ( 2a plus ( n - 1) x d ) then, s10 - 10/2 ( 2x6 plus (10-1) x 3) so, s10 - 5 ( 12 plus 9x3 ) , s10 - 5 (12 plus 27) then, s10 - 5 ( 39) , s10 -195

Answer 2

Answer:

195

Step-by-step explanation:

For an A.P. a = 6, d = 3

Sn = n/2 [2a + (n – 1) d]

∴  S10 = 10/2 [2a + (10 – 1) 1]

∴  S10 = 5 [2 (6) + 9 (3)]

∴  S10 = 5 (12 + 27)

∴  S10 = 5 (39)

∴  S10 = 195

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