For an AP, if t_1=22,t_n= (-11) and s_n=66 then find n.
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Answer:
First term =22
nth term =-11
a+(n-1)d=-11
22+(n-1)d=-11
(n-1)d=-11-22
(n-1)d=-33
Sn=66
n/2[2a+(n-1)d]=66
n[2×22+(-33)]=132
n[44-33]=132
n×11=132
n=132/11
n=12
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