For an ap if t4 is 20 ,t7 is 32 then find,a ,d and tn
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GIVEN:-
In an AP 4th term = 20,7th term = 32, find
a, d & tn.
Therefore:- (1) - (2)
4th term = a + 3d = 20 ........(1)
7th term = a + 6d = 32 ........(2)
- 3d = -12
d = -12/-3
d = 4.
'd' value in equation (1)
a+ 3(4) = 20
a + 12 = 20
a = 20-12
a = 8.
therefore a = 8 & d = 4.
Therefore:- tn = a + (n-1)d
tn = 8 + (n-1)4
tn = 8 + 4n-4
tn = 4n + 4.
Hence proved ........
I hope it is helpful to you....
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