Question

for an AP it is given that the first term is equal to 5 common difference is equal to 3 and the end term a n is equal to 50 find and and sum of first n terms of the AP

Answer 1

Answer:

Given: a=5

d=3

An=50

An=a+(n-1)d

50=5+(n-1)3

=45=(n-1)3

=n-1=15

n=16.

Sn=n/2(a+An)

=16/2(5+50)

=8×55

=440.

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Step-by-step explanation:

Answer 2

Answer:

$given \: a = 5 \\ d= 3 \\an = 50 \\ an = a +n - 1d \\ 50 = 5 + n- 1 = 3 \\ 45 = n - 1 \times 3 \\ n - 1 = 15 \\ n= 16 \\ \\ now.. \\ sn = n \div 2 a + an \\ 16 \div 2 \times 5 + 50 \\ 8 \times 55 \\ = 440$