Question

for an AP S27=810 find T10=​

Answer 1

Answer:

S27 =810

Sn = n/2[a+(n-1)d

810 = 27/2[a+(27-1)d

810×2/27 = a+26d

60 = a + 26d

a = 60 - 26d...............1

T10 = a + 9d ...............2

put value 1 in 2

T10 = 60 - 26d + 9d

T10 = 69 - 17d