for an AP S4-S3=3d?
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Answer:
s4=4/2{2a+3d}=2{2a+3d}=4a+6d (i)
s3=3/2{2a+2d}=3/2×2{a+d}=3a+3d (ii)
(i)×3-(ii)×4
12a+18d
12a+12d
(-)
________
6d
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