For an AP show that tm+tm+2n=2tm+n?
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tm+n+tm-n
= [ t + (m+n-1)d ] +[ t + (m-n-1)d ]
= 2t + d(m+n-1 + m-n-1)
= 2t + d(2m-2)
= 2[ t + d(m-1)]
= 2tm
= RHS
= [ t + (m+n-1)d ] +[ t + (m-n-1)d ]
= 2t + d(m+n-1 + m-n-1)
= 2t + d(2m-2)
= 2[ t + d(m-1)]
= 2tm
= RHS
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