Question

for an ap Sn=n^2-n+1, the second term is​

Answer 1

Answer:

Given :- Sn = n²(n+1)

Solution :

We know that,

Sn = n/2[ 2a + (n-1)d ]

n? (n+1) = n/2 [ 2a + (n-1)d]

Putting n as 1, to get value of 'a' (1)² (1+1) = 1/2 [ 2a + (1-1)d] 1 (2) = 1/2 [ 2a + o] 2. =

a

Taking n as 2 to get value of d

(2) (2+1) = 2/2 [ 2a + (2-1)d] 4 (3). = 1[ 2(2) + d]

12. = 4 + d

12 - 4 = d

8 d

So, d is 8

2nd term = a + d

= 2 + 8

= 10

Therefore the first term of AP is 2 and the second term of AP is 10

HOPE IT HELPS YOU!!

Answer 2

Answer:

a 2 = 5

Step-by-step explanation:

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