Question

For an AP sum of first 11 terms=6050,11th term=61, then value of a is

Answer 1

Answer:

1039

Step-by-step explanation:

Given S₁₁ = 6050 & t₁₁ = 61 , find a

by formula Sₙ = n/2 (a+l)  

where , n is the no. of terms

            a is the first term of the sequence

            l is the last term of the sequence (here t₁₁ = l = 61)

therefore,

S₁₁ = 11/2 (a + 61) = 6050

    => a+61 = 6050(2/11) = 550 * 2 = 1100

   => a = 1100 -61 = 1039

a+10d = 61

1039+10d =61

10d = 61-1039

d = -97.8