Question

for an AP t1 =1 and tn =149 then find sn​

Answer 1

$T_{1} =1\\T_{n} = 149=l\\\\S_{n} = \frac{n}{2}(a+l)\\\\S_{n} = \frac{n}{2}(1+149)\\\\S_{n} = \frac{n}{2}(500)S_{n} = 250n$

hope it helps u

Answer 2

Answer:hope this helps you mate

Step-by-step explanation:Sn=$\frac{n}{2}$(a+∫)

                                                =$\frac{n}{2}$(1+149)

                                                =$\frac{n}{2}$×150

                                                =75n