Question

For an AP t1=2 , tn = 41 and Sn=860 what is a value of n

Answer 1

Answer:

Here ur answer

Step-by-step explanation:

given -

SN = 860

t1 =2

tn= 41

n = ?

SN = n/2 ( 2a +{n-1} d) = 860

n/2 ( 2×2+(n-1)d)= 860

n/2 (tn + t1 ) =860

n/2 (41+2)=860

n/2(43)=860

n/2=860/43

n=860×2/43

n= 40