Math, asked by himanshupatil2004, 10 months ago

for an AP t3=17,t7=37,then S16=?

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Answered by kkRohan9181

0

Answer:

For an A.P, t3=17, t7=37. Find S16 . ... 37 = a+ 6d. ... S16 = n/2 (2a+(n- 1)d) ... 34+3=1951+2= 572+9=1412+5=?.

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