Question

for an AP the 6th term is 19 and the 17th yerm is 41. find the 40th term of the AP.

Answer 1

Hey Guys,

1)6th term , 2) 17th term,
a+5d =19 a+16d=41
Subtract 1 from 2
11d =22
d =2, put in 1
a=19-10 =9

a40th = 9+(39)2= 87 .

Thanks.

Answer 2

Heya mate, Here is ur answer

a6=19

we know that

an=a+(n-1)d

so, a6 = a +(6-1)d

a6=a+5d

a+5d=19

a=19-5d----(1)

a17=41

a+(17-1)d=41

a+16d=41 ---(2)

Using value of a from eq (1) in eq (2)

19-5d+16d=41

19+11d =41

11d =41-19

11d =22

d=22/11

d=2

a=19-5d

a=19-5×2

a=19-10

a=9

a40=a+(40-1)d

a40=a+39d

a40=9+39×2

a40=9+78

a40=87

$<b><u>So,40th term of the AP is 87.</u></b>$

Warm regards

@Laughterqueen

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