Question

For an AP whose a is 1 and d is 3/4 what are the first three terms

Answer 1

Step-by-step explanation:

If a=1 and d=3/4

then a2=a+d=1+3/4=1.75.

a3=a+2d=1+1.5=2.5. (2d=2×3÷4=1.5)

a4=a+3d=1+2.25=3.25. (3d=3×3÷4=2.25)

so the terms of the a.p are 1,1.75,2.5,3.25.........

this is correct

hope this helps you