Chemistry, asked by neha8784, 10 months ago

For an aqueous solution of nacl the observed molecular weight of nacl will be

Answers

Answered by meenugautamp
1

Answer:

60.5 amu

Na = 25 ,Cl = 35.5

NaCl

1*25 +1*35.5

25+35.5

60.5amu

Answered by cutydoll
6

Answer:

hey here is your answer....

Attachments:
Similar questions