Chemistry, asked by neha8784, 1 year ago

For an aqueous solution of nacl the observed molecular weight of nacl will be

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Answered by meenugautamp

1

Answer:

60.5 amu

Na = 25 ,Cl = 35.5

NaCl

1*25 +1*35.5

25+35.5

60.5amu

Answered by cutydoll

6

Answer:

hey here is your answer....

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