for an ARITHMETIC PROGRESSION 4, 9,14 ..........then t11=
a) 49
b)54
c)59
d)44
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Answered by
3
Step-by-step explanation:
I guess this is the only answer
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Answered by
4
Answer:
b.) 54
Step-by-step explanation:
Given series is 4,9,14,....
Clearly, the given sequence is an AP with first term a=4 and the common difference d=5.
We know, a n
=a+(n−1)d
Now, t 11
=a+10d
∴t 11
=4+10×5=54
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