Question

For an electric dipole pli at origin, find the value
of 'tand' at point A(3, 4), Here 'S' is the angle made
by resulting electric field at point A with +ve x-axis.
Answer:​

Answer 1

Answer:

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Answer 2

Electric dipole :

Explanation:

• An electric dipole is a pair of equal and opposite charges separated by a small distance.
• In an electric dipole, the magnitude of both the charges will be the same but with different magnitude.

• Let an electric dipole moment is $\bar_P$.

• Let the electric field at a point at the x-axis is P.

• Let ' S ' is the angle made by the resulting electric field at point A with a positive x-axis.

        $\displaystyle tanS = \frac{1}{2}\ tan\theta$

• Let ( S + θ ) is the value of the position vector makes an angle θ.

• Now resolve the component of E,

       $\displaystyle E\ cosS = \frac{2p\ cos\theta }{4\pi \epsilon_0r^3}$    ...(1)

      $\displaystyle E\ sinS = \frac{p\ sin\theta }{4\pi \epsilon_0r^3}$     ...(2)

• Divide eq (2) by eq (1)

     $\displaystyle \mathbf{tan\ S = \frac{1}{2} tan\ \theta}$

This is the required formula.