Physics, asked by shriyaljamwal, 4 months ago

for an electric field of 10 n/c a current density of 2 A/m² is produced in a metallic conductor. The electric field required for a current density of 1 A/m² is​

Answers

Answered by amoghnasa
1

Explanation:

J = SIGMA x E

J1/J2 = E1/E2

2/1=10/E2

thus,

E2= 5n/C

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