Question

For an electric heater rated 2.2 kW-220 V. Calculate the following:
The current flowing through the circuit is ________ A

the energy consumed in 1 hour is __________ X 10^6 Joule

The resistance of the heater is _________________ ohm.

if this heater is used for 2 hours daily, then find the electricity bill for one month (30 days). The cost of one unit of electricity is 8 rupees.

There is a second heater of 3.3 kW – 220 volt. What is the ratio of their resistances?​

Answer 1

Explanation:

the current flowing through the circuit

P=V2/R 220×220/R

2.2=220×220/R

R=220×220/2.2 =

22000

V=IR

I=V/R

220/22000=0.01