for an electric iron of 1Kw rating at 200V, fuse of how much capacity is to be used?
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Answer:
a fuse of capacity of 5 A (but slightly more)
Explanation:
first we have to calculate the current required by this iron to operate
ie
P=VI
V=200 V
P=1000 W
I=P/V
=1000/200
=5 A
therefore a fuse of 5 A is enough
(though actually it should be slightly greater than 5A )
Hope this helps.
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