Question

for
an electron accelerated by the potential difference of 49V.
calculate
1. debrogei
wave length
2.momentum of it
​

Answer 1

Answer:

ANSWER

(a) Potential difference, V=56 volts

At equilibrium, Kinetic energy is accelerating potential.

2

mv

2

=eV

v=4.44×10

6

m/s

P=mv

⇒9.1×10

−31

×4.44×10

6

=4.04×10

−24

where m is the mass of the electron.

(b) De Broglie wavelength is given by

λ=

V

12.27×10

−10

⇒ 56

12.27×10

−10

=0.164 nm