Question

for an electron accelerated through a potential diffrence of 56V calculate
1), momentum
2), de-Broglie wavelength

spamming i ll report your 20 answers​

Answer 1

) de Broglie wavelength of the electrons accelerated through a potential difference of 56 V. Therefore, the momentum of each electron is 4.04 × 10−24 kg m s−1 . ... Therefore, the de Broglie wavelength of each electron is 0.1639 nm.

Answer 2

(b) de Broglie wavelength of the electrons accelerated through a potential difference of 56 V. Therefore, the momentum of each electron is 4.04 × 10−24 kg m s−1 . ... Therefore, the de Broglie wavelength of each electron is 0.1639 nm.