Question

for an electron to have the same de Broglie wavelength as the of a deuteron its velocity should be how many times of that deuteron ​

Answer 1

Hey Dear,

◆ Answer -

ve = 3674 vd

◆ Explanation -

de Broglie's wavelength of deuteron is calculated by -

λ = h/(md.vd) ...(1)

For electron having same de Broglie's wavelength -

λ = h/(me.ve) ...(2)

From (1) & (2),

h/(md.vd) = h/(me.ve)

me.ve = md.vd

ve/vd = md/me

ve/vd = 3.343×10^-27 / 9.1×10^-31

ve/vd = 3674

ve = 3674 vd

Therefore, velocity of electron should be 3674 times that of deuteron to have same de Broglie's wavelength.

Thanks dear...

Answer 2

Answer:

the explanation in above answers is correct

Step-by-step explanation:

but the answer is 3672