Question

For an element with atomic number 29

i) Write the electronic configuration.

ii) Write the value of n and l for its electron in its valence shell.

b) Name the set of d-orbitals having the electron density along the axis.​

Answer 1

Answer:

i)The symbols used for writing the electron configuration start with the shell number (n) followed by the type of orbital and finally the superscript indicates how many electrons are in the orbital. For example:-So Oxygen's electron configuration would be O 1s22s22p4.

ii) The value of l is dependent on the principal quantum number n. Its general formula is (n-1). Conclusion: As no of electrons in this element are 24. So in first shell, there are 2 electron, in 2nd shell there are 8 electron while 3rd shell there are 14.

iii)So, dz2,dx2−y2 pairs of d-orbitals will have electron density along the axis.

Explanation:

Hope it helps you

Answer 2

i) The electronic configuration of an element with atomic number 29 is

$1s^{2},2s^{2},2p^{6},3s^{2},3p^{6},3d^{10},4s^{1}$.

ii) the value of n and l for its electron in its valence shell is n=4 and l=0.

b) $d_{z^{2} } ,d_{x^{2}-y^{2} }$ are the set of d-orbitals having the electron density along the axis.​