Physics, asked by manhassanjeet535, 1 year ago

For an emission of wavelength 5000 Angstrom, at what temperatures both spontaneous and stimulated emissions will be same?

Answers

Answered by Ursus
1

For an emission of wavelength 5000 Angstrom, both spontaneous and stimulated emissions will be same at temperature 28869.6 K

The Temperature is calculated by the formula

\frac{N}{n}=e^{-hc/λKT}-1

here, n is number of spontaneous emission, N number of stimulated emission, h is Planck's constant,  c is speed of light, K is Boltzmann constant, and T is temperature

Plugging the values in the above equation

1=e^{-6.64*10^(-34)*3*10^8/(5000*10^(-10)*1.38*10^(-23)*T}-1

T=28869.6 K

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