Chemistry, asked by xoxolucky, 10 months ago

. For an enzyme-substrate reaction, a plot between 1/V and 1/[S]
yields a slope of 40s. If the enzyme
concentration is 2.5 uM, then the catalytic efficiency of the enzyme is
a) 40 Lmol's
b) 10 Lmol's'
c) 10'Lmol's
d) 10 Lmol's' (CSIR NET DEC 2014)

Answers

Answered by Anonymous
2

the Km of my enzyme is about 1µM. (in case I ignored the inhibition).

The specific activity with 5µM substrate is 2µM/min/mg. (in my case this is Vmax when I ignore the inhibition).

The specific activity with 10µ substrate is 1,7µM/min/mg. (it is lower here, that means here we have inhibition).

The specific activity with 20µM substrate is 1,5µM/min/mg. (again inhibition).

So, the answer is a) 40 Lmol's

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