Question

for an equation 2y^2-5y+6=0,how many solutions are there?​

Answer 1

Answer:

I didn't know

Step-by-step explanation:

sorry bro

Answer 2

Answer:

There will be 0 real roots and 2 imaginary roots as it is a quadratic equation and it's discriminant is negative.

Step-by-step explanation:

2y^2-5y+6=0

D = b^2-4ac

= (-5)^2 -4(2)(6)

= 25-48 = -23

As it is negative it will have 0 real roots and 2 imaginary roots which can be founded by the following equation:

y =

$( - b \frac{ + }{} \sqrt{ {b}^{2} - 4ac}) \div 2a$