Question

For an equation
${x}^{2} + 4x + k = 0$. If roots are real and equal, what is the value of k?​

Answer 1

Answer:

6

Step-by-step explanation:

x+4x+k=0

k=6

when an equation is revers

Answer 2

Answer:

K = 4

Step-by-step explanation:

x²+ 4x + k =0

Comparring with ax² + bx + c = 0, we get

a=1     b=4    c=k

b²-4ac = (4)² - 4×1×k

            = 16 - 4k

The equation has real and equal roots,

16 - 4k = 0

-4k = -16

k = -16/-4

⇒ k = 4