For an examination, 1200 of the candidates were boys. If 50% of the boys and 40% of the girls were successful, find the number of girl candidates, given that 46% of the total number of candidates were successful.
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The number of the boys is 1200, and that of the girls is not known (so assume it to be 'y').
Therefore the total number of the whole students
would be=(1200 + y).
And they said 40% of the girls were sucessfull
Recalling the method of finding %, thus:
40= y × 100/1200 + y
=> 40= 100y/1200 + y.
By cross multiplication:
40 (1200 + y) = 100y
=> 48000 + 40y = 100y
By collecting the like terms:
48000 = 100y – 40y
=> 48000 = 60y
Dividing both sides by 60
48000/60 = 60y/60
=> 800 = y.
Therefore, the number of the girls is 800.
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