Chemistry, asked by PerfectSmoker909, 27 days ago

For an ideal gas, the work of reversible expansion under isothermal condition can be calculated by using the expression w = – nRT ln(Vf/Vi)
A sample containing 1.0 mol of an ideal gas is expanded isothermally and reversibly to ten times of its original volume, in two separate experiments.
The expansion is carried out at 300 K and at 600 K respectively. Choose the correct option.
(i) Work done at 600 K is 20 times the work done at 300 K.
(ii) Work done at 300 K is twice the work done at 600 K.
(iii) Work done at 600 K is twice the work done at 300 K.
(iv) ΔU = 0 in both cases
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Answered by yash83dei
1

Answer:

For an ideal gas, the work of reversible expansion under isothermal condition can be calculated by using the expression w=−nRTIn

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. A sample containing 1.0mol of an ideal gas is expanded isothermally and reversibly to ten times of its original volume, in two separate experiments. The expansion is carried out at 300K and at 600K respectively. Choose the correct option.

Note: Two or more options may be correct.

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