Question

For an inclined plane, a body starts to move when the angle of inclination is 450

or above. What would be the coefficient of self adjusting friction of the slope? ans fast plzz​

Answer 1

Explanation:

For an inclined plane, less force is put into moving an object up the slope than if the object were lifted straight up, so the mechanical advantage is greater than 1. The more gradual the slope of the inclined plane, the less input force is needed and the greater the mechanical advantage.

When we resolve the FBD we get:

Vertical force: N=mgcosθ

Horizontal force : mgsinθ−μN=ma

So ma=mgsinθ−μmgcosθ

∴a=gsinθ−μgcosθ _____(1)

As given in the question:

s=ct 2dtds =2cta= dt 2d 2 s =2c

From eq−1:a=g(sinθ−μcosθ)=2c

2c=g(sinθ−μcosθ)

Given: c=1.73 and θ=45 0

Therefore, μ=0.5anda=2c=2 root 3 m/s 2

Answer 2

Answer:

I hope you understand

Explanation:

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